Dua buah benda masing masing bermuatan -20×10^-6 dan 24×10^-6 . Jika kedua muatan terpisah 12cm . Hitunglah berapa gaya interaksi antar kedua muatan?

12 cm =12.10^-2
F= k. Q1.Q2
---------
r^2
= 9.10^9. 20×10^-6.24×10^-6
----------------------------
12.12.10^-4
= 3.10^2

[tex]listrik \: statis[/tex]
[tex]q1 = - 20 \times 10^{ - 6} [/tex]
[tex]q2 = 24 \times 10 ^{ - 6} [/tex]
[tex]k = 9 \times 10 ^{9} [/tex]

r = 0,12 m = 12 × 10^-2


F = k × q1 × q2 /r^2

F = 9 ×10^9 × 20 × 10^-6 × 24 × 10^-6/12×10^-2 × 12×10^-2

F = 90 × 24 × 10^9-6-6/12 × 12 × 10^-4

F = 90 × 2 × 10^-3 / 12 × 10^-4

F = 90 × 10^-3 / 6 × 10^-4

F = 15 × 10^-3/10^-4

F = 15 × 10^-3+4


[tex]f = 15 \times 10 ^{1} newton[/tex]