Matematika

Pertanyaan

perbandingan persegi panjang
p : l
3 : 2

keliling = 40 cm
maka luasnya

1 Jawaban

  • misal :
    p = 3a
    l = 2a

    K = p + p + l + l
    40 = 3a + 3a + 2a + 2a
    40 = 10a
    a = 40/10 = 4
    a = 4

    p = 3a = 3(4) = 12
    l = 2a = 2(4) = 8

    L = p × l = 12 × 8 = 96cm2

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