Matematika

Pertanyaan

nilai dari ekspresi
[tex] \frac{ {}^{3} log \sqrt{6} }{( {}^{3} log18) {}^{2} - ( {}^{3} log2 ) {}^{2} } [/tex]

2 Jawaban

  • 1/2(3log6) / 3log6^2 . 3log3^2
    1/2(3log6) / 2(3log6) . 2
    (1/2) / 4 =1/8
  • [tex] \frac{ ^{3} log \sqrt{6} }{( ^{3} log18)^{2} - ( ^{3} log2 )^{2} } [/tex]

    *Dengan sifat [tex] a^2 - b^2 = (a+b)(a-b) [/tex] didapat

    [tex] = \frac{^3log\sqrt{6}}{(^3log18+^3log2)(^3log18-^3log2)} \\ = \frac{^3log\sqrt{6}}{(^3log(18.2))(^3log(18:2))} \\ = \frac{^3log\sqrt{6}}{(^3log36)(^3log9)} \\ = \frac{^3log\sqrt{6}}{^3log36} . \frac{1}{^3log9} \\ = ^{36}log\sqrt{6} . \frac{1}{2} \\ = ^{6^2}log6^{\frac{1}{2}} . \frac{1}{2} \\ = \frac{1}{4} . \frac{1}{2} \\ = \frac{1}{8} [/tex]

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