Matematika

Pertanyaan

Tentukan nilai-nilai positif X agar berlaku 9 x pangkat 2 per 3 + 4 x pangkat min 2 per 3 = 37

1 Jawaban

  • Misal :
    x^2/3 = a

    9a + 4/a = 37
    9a² - 37a + 4 = 0
    (9a - 1)(a - 4) = 0
    a = 1/9 atau a = 4

    a = 1/9
    x^2/3 = 3^-2
    x^1/3 = 3^-1
    x = 3^-3
    x = 1/27 ✔

    a = 4
    x^2/3 = 2²
    x^1/3 = 2
    x = 2^3
    x = 8 ✔

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