F'(x) = 6x²+2x-4 dan F(2) = 0 maka F(x)=?

f'(x) = 6x^2 + 2x - 4, f(2) = 0
f(x) adalah integral f' (x)
maka f (x ) = 2x^3 + x^2 - 4x + c
f (2) = 0
2(2)^3 + 2^2 - 4.2 + c = 0
16 + 4 - 8 + c = 0
12 + c = 0
c = -12
Jadi f(x) = 2x^3 + x^2 -4x -12