Tentukan akar kuadrat dari 2X2 - 3x +4 = 0

Persamaan Kuadrat.

ax² + bx + c = 0
2x² - 3x + 4 = 0
a = 2, b = -3, dan c = 4

[tex]\displaystyle x_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\ =\frac{-(-3)\pm \sqrt{(-3)^2-4(2)(4)}}{2(2)}\\ =\frac{3\pm i\sqrt{23}}{4}\\ x_1=\frac{3}{4}+\frac{\sqrt{23}}{4}i~\vee x_2=\frac{3}{4}-\frac{\sqrt{23}}{4}i[/tex]

Catatan:
Akar-akarnya imanjner. i = √-1