Tentukan PGL yang melalui titik (3,5) dan tegak lurua garis berikut: a.y=2x b.3x+y+6=0 c.5x-2y+7=0

MATEMATIKA
Persamaan Garis Lurus

(x1, y1) = (3, 5)

a) y = 2x
m'a = 2
m'h = - 1 ÷ 2 = - 1/2
PGL :
y - y1 = m'h (x - x1)
y - 5 = - 1/2 (x - 3)
2y - 10 = - 1 (x - 3)
2y - 10 = - x + 3
2y + x - 10 - 3 = 0
2y + x - 13 = 0 《 Jawaban (a)

b) 3x + y + 6 = 0
m'b = -3/1 = - 3
m'i = - 1 ÷ - 3 = 1/3
PGL :
y - y1 = m'i (x - x1)
y - 5 = 1/3 (x - 3)
3y - 15 = x - 3
3y - x - 15 + 3 = 0
3y - x - 12 = 0 《 Jawaban (b)

c) 5x - 2y + 7 = 0
m'c = - 5 / - 2 = 5/2
m'j = - 1 ÷ 5/2 = - 1 × 2/5 = -2/5 = - 2/5
PGL :
y - y1 = m'j (x - x1)
y - 5 = -2/5 (x - 3)
5y - 25 = -2 (x - 3)
5y - 25 = -2x + 6
5y + 2x - 25 - 6 = 0
5y + 2x - 31 = 0 《 Jawaban (c)