intergral tentu atas 1 bawah 0 (x+akar x)² dx =

InTegraL

∫(x + √x)² dx [1...0]
= ∫(x² + 2x√x + x) dx
= ∫(x² + 2x^3/2 + x) dx
= 1/3 x³ + 4/5 x^5/2 + 1/2 x²
= 1/3 . 1³ + 4/5 .1^5/2 + 1/2 . 1² - 0
= 1/3 + 4/5 + 1/2
= (10 + 12 + 15)/30
= 37/30 ✔