Matematika

Pertanyaan

sederhanakan hasil kali bentuk aljabar dari a.4(3a+2) b.(×+3)(×-2) c.(2×-1)(×+2y-3) .......tolong yaaa kak dengan caranya

2 Jawaban

  • A. 4(3a+2) = 12a+8

    B. (X+3)(X-2) = X^2-2x+3x-6 = x^2+x-6

    C. (2x-1)(x+2y-3) = 2x^2+4xy-6x-x-2y+3 = 2x^2+4xy-7x+3 = x(2x+4y-7)+3
  • a.4(3a+2)
    = (4 . 
    3a) + (4 . 2)
    = 12a + 8

    b.(x + 3)(x - 2)
    = (x . x) + (x . (-2)) + (3 . x) + (3 . (-2))
    = x
    ² + (-2x) + (3x) + (-6)
    = x² + x - 6

    c. (2x - 1)(x + 2y - 3)
    = (2x . x) + (2x . 2y) + (2x . (-3)) - (1 . x) - (1 . 2y) - (1 . (-3))
    = 2x
    ² + 4xy + (-6x) - x - 2y - (-3)
    = 2x² + 4xy - 7x - 2y + 3

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