log (logx + 3) = log 2 bersama syaratnya please butuh

log (logx + 3) = log 2
log di kedua ruas dapat saling dihilangkan sehingga
log x + 3 = 2
log x = 2-3
log x = -1
log x = log 10^-1
sehingga
x = 10^-1 = 1/10
= 0,1

log (log x+3) = log 2
log x+3 = 2
log x+3 = log 10²
x + 3 = 100
x = 100-3 = 97