dik 3 log 6 =p,3log2 =q nilai24log288=

³log6 = p
³log2 = q

maka nilai
²⁴log288
= ³log288 / ³log24
= ³log(2⁵ . 3²) / ³log(2³ . 3)
= (5.³log2 + 2.³log3) / (3 .³log2 + ³log3)
= (5q+1)/(3q+1)