diberikan sistem persamaan 1/x+2/y=1 1/x+4/z=0 1/y+2/z=1 Nilai dari 1/x+1/y+1/z adalah .....

1/x + 2/y = 1
1/x = 1 - 2y

1/y + 2/z = 1
2/z = 1 - 1/y

1/x + 4/z = 0
1/x + 2(2/z) = 0
1/x + 2(1 - 1/y) = 0
1/x + 2 - 1/y = 0
1/x - 1/y = -2
(1 - 2/y) - 1/y = -2
1 - 3/y = -2
3/y = 1 + 2 = 3
3(1/y) = 3
1/y = 1

1/x = 1 - 2/y = 1 - 2(1/y) = 1 - 2(1) = - 1
1/x = -1

1/x + 4/z = 0
4/z = - 1/x
4(1/z) = -(-1)
1/z = 1/4 = 0,25

Jadi,
1/x + 1/y + 1/z = -1 + 1 + 0,25 = 0,25